PHP time ago calculation
- 5 Comment
The new web 2.0 displays time and date not in old style manner like 12.30 pm Jan 200 7. The new generation need relative time like 2 hours ago, 6 months ago, 4 years ago, very old etc. So if you save the timestamp of a particular content creation in database we can simply show this ‘ago time calculation’ using the following algorithm.
//$datefrom is the timestamp for the content , and you can leave the $dateto value to see the current delay
function TimeAgo($datefrom,$dateto=-1)
{
// Defaults and assume if 0 is passed in that
// its an error rather than the epoch
if($datefrom<=0) { return "A long time ago"; }
if($dateto==-1) { $dateto = time(); }
// Calculate the difference in seconds betweeen
// the two timestamps
$difference = $dateto - $datefrom;
// If difference is less than 60 seconds,
// seconds is a good interval of choice
if($difference < 60)
{
$interval = "s";
}
// If difference is between 60 seconds and
// 60 minutes, minutes is a good interval
elseif($difference >= 60 && $difference<60*60)
{
$interval = "n";
}
// If difference is between 1 hour and 24 hours
// hours is a good interval
elseif($difference >= 60*60 && $difference<60*60*24)
{
$interval = "h";
}
// If difference is between 1 day and 7 days
// days is a good interval
elseif($difference >= 60*60*24 && $difference<60*60*24*7)
{
$interval = "d";
}
// If difference is between 1 week and 30 days
// weeks is a good interval
elseif($difference >= 60*60*24*7 && $difference <
60*60*24*30)
{
$interval = "ww";
}
// If difference is between 30 days and 365 days
// months is a good interval, again, the same thing
// applies, if the 29th February happens to exist
// between your 2 dates, the function will return
// the 'incorrect' value for a day
elseif($difference >= 60*60*24*30 && $difference <
60*60*24*365)
{
$interval = "m";
}
// If difference is greater than or equal to 365
// days, return year. This will be incorrect if
// for example, you call the function on the 28th April
// 2008 passing in 29th April 2007. It will return
// 1 year ago when in actual fact (yawn!) not quite
// a year has gone by
elseif($difference >= 60*60*24*365)
{
$interval = "y";
}
// Based on the interval, determine the
// number of units between the two dates
// From this point on, you would be hard
// pushed telling the difference between
// this function and DateDiff. If the $datediff
// returned is 1, be sure to return the singular
// of the unit, e.g. 'day' rather 'days'
switch($interval)
{
case "m":
$months_difference = floor($difference / 60 / 60 / 24 /
29);
while (mktime(date("H", $datefrom), date("i", $datefrom),
date("s", $datefrom), date("n", $datefrom)+($months_difference),
date("j", $dateto), date("Y", $datefrom)) < $dateto)
{
$months_difference++;
}
$datediff = $months_difference;
// We need this in here because it is possible
// to have an 'm' interval and a months
// difference of 12 because we are using 29 days
// in a month
if($datediff==12)
{
$datediff--;
}
$res = ($datediff==1) ? "$datediff month ago" : "$datediff
months ago";
break;
case "y":
$datediff = floor($difference / 60 / 60 / 24 / 365);
$res = ($datediff==1) ? "$datediff year ago" : "$datediff
years ago";
break;
case "d":
$datediff = floor($difference / 60 / 60 / 24);
$res = ($datediff==1) ? "$datediff day ago" : "$datediff
days ago";
break;
case "ww":
$datediff = floor($difference / 60 / 60 / 24 / 7);
$res = ($datediff==1) ? "$datediff week ago" : "$datediff
weeks ago";
break;
case "h":
$datediff = floor($difference / 60 / 60);
$res = ($datediff==1) ? "$datediff hour ago" : "$datediff
hours ago";
break;
case "n":
$datediff = floor($difference / 60);
$res = ($datediff==1) ? "$datediff minute ago" :
"$datediff minutes ago";
break;
case "s":
$datediff = $difference;
$res = ($datediff==1) ? "$datediff second ago" :
"$datediff seconds ago";
break;
}
return $res;
}
5 Comments on this post
Trackbacks
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Binny V A said:
When posting code, could you put it in pre tag? Otherwise the indentation is lost.
February 2nd, 2008 at 12:00 am -
Bill said:
Exactly what I was looking for! Great job. Thanks for sharing.
June 19th, 2008 at 11:34 pm -
mfields said:
Hi,
Is there a license on this code…
Looks great would love to use it!!!
Thanks!!!October 1st, 2008 at 7:56 pm -
Tom said:
Brilliant - just what I needed. Thank you.
November 6th, 2008 at 11:50 pm -
Venkatesan said:
Really Great script. It helps me lot.
Thanks.December 22nd, 2008 at 4:24 am





